1.

If 0 lt theta lt pi/2, x = sum_(n=0)^(oo)cos^(2n) theta, y =sum_(n=0)^(oo)sin^(2n)theta, and z=sum_(n=0)^(oo) cos^(2n)theta sin^(2n) theta then show that (i) xyz=xy+z (ii) xyz=x+y+z

Answer»

`xz+yz=xy+z`
`xyz=yz+x`
`xy+z=xy+zx`
`x+y+z=xyz+z`

ANSWER :A


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