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If `(1-p)`is a root of quadratic equation `x^2+p x+(1-p)=0,`then find its roots.A. `-1, 2`B. `-1, 1`C. `0, -1`D. 0, 1 |
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Answer» Correct Answer - C Since (1-p) is a root of the given equation. `therefore" "(1-p)^(2) + p(1-p) + (1-p) = 0` `rArr" "(1-p) {(1-p)+p+1} = 0 rArr 2 (1-p) = 0 rArr p = 1` Substituting p = 1 in the given equation, we get `x^(2) + x = 0 rArr x = 0, -1` Hence, 0 and -1 are the roots of the given equation. |
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