InterviewSolution
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InterviewSolution
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If 10.0 g `V_2O_5` is dissolbed in acid and reduced to `V^(2+)` by treatment with tin (Sn) metal how many moles of `I_2` could be reduced by the resulting `V^(2+)` solution as it is oxidised to `V^(4+)`? (Atomic weight of V is 51) |
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Answer» `V_(2)^(5+)+6erarr2V^(2+)` `ZnrarrZn^(2+)+2e` `V^(2+)rarrV^(4+)+2e` `I_(2)+2erarr2I^(-)` and Meq.of `V^(2+)(v.f=3)=` Meq.of ` V_(2)O_(5)(v.f=6)` `=(10)/(182//6)xx1000` Meq.of `V^(2+)(v.f.=2)=(10)/(182//6)xx1000xx(2)/(3)` Meq.of `V^(2+)(v.f=2)=` Meq.of `I_(2)` `(10xx6)/(182)xx1000xx(2)/(3)=` Meq.of `I_(2)` or Meq.of `I_(2)=219.78` `m` Mole of `I_(2)=(219.78)/(2)=109.89` Mole of `I_(2)=(109.89)/(1000)` Mole of `I_(2)=0.1098` |
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