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If 1000 gms of sand is sieved through 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 gms, 100 gms, 150 gms, 200 gms, 350 gms and 200 gms respectively, then the fineness modulus of the sand is1. 2.002. 2.603. 2.754. 2.90 |
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Answer» Correct Answer - Option 2 : 2.60 Concept: Fineness modulus (F.M) It is a numerical index of fineness or grading of aggregate. It gives some idea of the average size of the aggregate. The value of fineness modulus is higher for coarse aggregate. \({\rm{F}}.{\rm{M}} = \frac{{{\rm{Cummulative\;percentage\;of\;material\;retained\;on\;each\;sieve}}}}{{100}}\) Classification based on Fineness modulus
Calculation:
Fineness modulus is given by \({\rm{F}}.{\rm{M}} = \frac{{{\rm{Cummulative\;percentage\;of\;material\;retained\;on\;each\;sieve}}}}{{100}}\) \({\rm{F}}.{\rm{M}} = \frac{{{\rm{260}}}}{{100}}=2.60\) Hence the fineness modulus of the sand is 2.60 |
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