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If 21y5 is a multiple of 9, where y is a digit, what is the value of y? |
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Answer» For a number to be a multiple of `9`, sum of all of its digits should be divisible by `9`. Sum of digits of gfiven number `= 2+1+y+5 = 8+y` So, `(8+y)` should be divisible by `9` if value of `y` is `1`. |
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