if 360g of urea is dissolved in 1000g of water. find the molarity of solution if density is 1.12g/mol.

if 360g of urea is dissolved in 1000g of water. find the molarity of s

1.	if 360g of urea is dissolved in 1000g of water. find the molarity of solution if density is 1.12g/mol.
Answer» 0.5Explanation:mass of solute(urea) = 360gmass of solvent(water) = 1000G Molarity = n/V n = NUMBER of moles of solute = mass given / MOLAR mass = 360/60 = 6 density of solution is 1.12g/mol m(soln.) = m(solute) + m(solvent) density(soln.) × V(soln.) = 360 + 1000 1.12 × Vol(soln.) = 1360V(soln.) = 1360/1.12 = 1214.28 ML = 1.21 L M = n/ V = 6/ 1.21 = 0.49 ~ 0.5