If `64x^(2) + (1)/(64 x^(2)) = 20` , then `8x - (1)/(4x)` can be `"_______"`A. 2B. 8C. 1D. 4

If `64x^(2) + (1)/(64 x^(2)) = 20` , then `8x - (1)/(4x)` can be `"___

1.	If `64x^(2) + (1)/(64 x^(2)) = 20` , then `8x - (1)/(4x)` can be `"_______"`A. 2B. 8C. 1D. 4
Answer» Correct Answer - D `64x^(2) + (1)/(16x^(2)) = 20` `(8x)^(2) + ((1)/(4x))^(2) = 20` `(8x)^(2) + ((1)/(4x))^(2) - 2(8x)((1)/(4x)) + 2(8x) ((1)/(4x)) = 20` `(8x - (1)/(4x))^(2) + 4 = 20` `(because (p-q)^(2) = p^(2) + q^(2) - 2pq)` `(8x - (1)/(4x))^(2) = 16` `8x - (1)/(4x) = 4`. Hence , the correct option is (d) .

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