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If a_(1) x^(3) + b_(1)x^(2) + c_(1)x + d_(1) = 0 and a_(2)x^(3) + b_(2)x^(2) + c_(2)x + d_(2) = 0 a pair of repeated roots common, then prove that |{:(3a_(1)","2b_(1)","c_(1)),(3a_(2)"," 2b_(2)","c_(1)),(a_(2)","b_(1)- a_(1)b_(2)","c_(2)a_(1)-c_(2)a_(1)","d_(1)a_(2)-d_(2)a_(1)):}|=0 |
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Answer» SOLUTION :If `f(x) = a_(1)x^(3) + b_(1) x^(2) + c_(1) x + d_(1) = ` has roots `alpha, alpha, beta,` then `g(x) = a_(2)x^(3) + b_(2)x^(2) + c_(2)x+ d_(2) = 0` must have roots `alpha, alpha, gamma` Hence,` a_(1) alpha^(3) + b_(1)alpha^(2)+ c_(1) alpha+ d_(1)= 0`(1) ` a_(2) alpha^(3) + b_(2)alpha^(2)+ c_(2) alpha+ d_(2)= 0`(2) Now, `alpha` is also a root of equation `f'(x) = 3a_(1)x^(2) + 2b_(1) x + c_(1) = 0` and `g'(x) = 3 a_(2) x^(2) + 2b_(2)x + c_(2)` = 0. Therefore, `3 a_(1) alpha^(2) + 2b_(1)alpha+ c_(1) = 0`(3) `3 a_(2) alpha^(2) + 2b_(2)alpha+ c_(2) = 0`(4) Also, from `a_(2) xx(1) - a_(1)xx(2)`, we have `(a_(2)b_(1)-a_(1)b_(2) )alpha^(2) + (c_(1) a_(2) - c_(2)a_(1))alpha + d_(1)a_(2) -d_(2)a_(1)= 0`(5) Eliminating `alpha` from (3),(4) and (5), we have `|{:(3a_(1)","2b_(1)","c_(1)),(3a_(2)"," 2b_(2)","c_(1)),(a_(2)","b_(1)- a_(1)b_(2)","c_(2)a_(1)-c_(2)a_(1)","d_(1)a_(2)-d_(2)a_(1)):}|=0` . |
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