InterviewSolution
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If α and β are the roots of the equation 2x2 + 2px + p2 = 0, where p is a non-zero real number, and α4 and β4 are the roots of x2 - rx + s = 0, then the roots of 2x2 - 4p2x + 4p4 - 2r = 0 are:1. Real and unequal.2. Equal and zero.3. Imaginary.4. Equal and non-zero. |
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Answer» Correct Answer - Option 3 : Imaginary. Concept: The solution to the quadratic equation Ax2 + Bx + C = 0 can also be given by: \(\rm x=\frac{-B\pm \sqrt{B^2-4AC}}{2A}\). The quantity B2 - 4AC is also called the discriminant.
The sum of both the roots of the quadratic equation Ax2 + Bx + C = 0 is \(\rm -\frac{B}{A}\) and the product of the roots is \(\rm \frac{C}{A}\).
Calculation: Using the expressions for the sum and the product of the roots, we have: α + β = -p ... (1) αβ = \(\rm \frac{p^2}{2}\) ... (2) α4 + β4 = r ... (3) Squaring equation (1), we get: α2 + β2 + 2αβ = p2 Using equation (2), we get: ⇒ α2 + β2 = 0 Squaring again, we get: ⇒ α4 + β4 + 2α2β2 = 0 Using equations (2) and (3), we get: ⇒ r = -\(\rm \frac{p^4}{2}\) ... (4) The discriminant of the equation 2x2 - 4p2x + 4p4 - 2r = 0 is: (-4p2)2 - 4(2)(4p4 - 2r) = 16p4 - 32p4 + 16r Using equation (4), we get: = 16p4 - 32p4 - 8p4 = -24p4, which is always negative for non-zero real p. Since the discriminant is < 0, the roots are imaginary. |
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