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    				| 1. | If a particle is moving on an parallel path given by `r=b cos omegat hati+asinomegat hatj`, then find its radial acceleration along `r`A. `omega r`B. `omega^(2)r`C. `-omega^(2)r`D. none of these | 
| Answer» (a) `(dr)/(dt)=-bomegat sin hati+aomega cos omegat hatj` `(d^(2)r)/(dt^(2))=-bomega^(2) sin omegat hati+aomega^(2) cos omegat hatj` `(d^(2)r)/(dt^(2))=-omega^(2) [b cos omegat hati+a sin omegat hatj]=-omega^(2)r` | |