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If `Ag^(+)+NH_(3)hArr[Ag(NH_(3))]^(+)`, `K_(1)=3.5xx10^(-3)` and `[Ag(NH_(3))]^(+)+NH_(3)hArr[Ag(NH_(3))_(2)]^(+)`, `K_(2)=1.74xx10^(-3)`. The formation constant of `[Ag(NH_(3))_(2)]^(+)` is :A. `6.08 xx 10^(-6)`B. `6.08 xx 10^(6)`C. `6.08 xx 10^(-9)`D. None of these |
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Answer» Correct Answer - A If a reaction occurs in two steps, the equilibrium constant for the overall reaction is given by the product of the equilibrium constants for the individual steps. `Ag^(o+) +NH_(3) hArr [Ag(NH_(3))]^(o+), K_(1) = 3.5 xx 10^(-3)` `[Ag(NH)_(3)]^(o+) +NH_(3) hArr [Ag(NH_(3))_(2)]^(o+), K_(2) = 1.7 xx 10^(-3)` `Ag^(o+) +2NH_(3) hArr [Ag(NH_(3))_(2)]^(o+)`, Over all `K = K_(1) xx K_(2)` `= 3.5 xx 10^(-3) xx 1.7 xx 10^(-3)` `= 5.95 xx 10^(-6)` |
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