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If alpha,beta are the roots of equation x^(2)-10x+2=0 and a_(n)=alpha^(n)-beta^(n) then sum_(n=1)^(50)n.((a_(n+1)+2a_(n-1))/(a_(n))) is more than |
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Answer» 12500 `a_(n+1)-10a_(n)+2a_(n-1)=0` `(a_(n+1)+2a_(n-1))/(a_(n))=10` `sum_(n=1)^(50)n.(10)=10.(50xx51)/(2)` `=250xx51=12750` |
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