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If alpha, beta, gamma are the eccentric angles of three points on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at which the normals are concurrent, then sin(alpha+beta)+sin(beta+gamma)+sin(gamma+alpha) is equal to______ |
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Answer» Eliminating `"tan"(delt)/2` from above, we will get `SIN(alpha+beta)+sin(beta+gamma)+sin(gamma+alpha)=0` |
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