If an experiment to measure coefficient of viscosity radius of tube measured r = (0.100 +- 0.001) cm and length 1 = (50.0 +- 0.1) cm and volume of fluid coming out of capillary in unit time is V = (0.25 +-0.01) cm//^(2). If pressure difference between end of tube is p = 10^(6) dyne/ cm^(2), then by using Poeisullie's law V=(pi pr^(4))/(8 eta l) Find coefficient of viscosity.

If an experiment to measure coefficient of viscosity radius of tube me

1.	If an experiment to measure coefficient of viscosity radius of tube measured r = (0.100 +- 0.001) cm and length 1 = (50.0 +- 0.1) cm and volume of fluid coming out of capillary in unit time is V = (0.25 +-0.01) cm//^(2). If pressure difference between end of tube is p = 10^(6) dyne/ cm^(2), then by using Poeisullie's law V=(pi pr^(4))/(8 eta l) Find coefficient of viscosity.
Answer» Solution :By using Poesullie.s law. `V=(pi p r^(4))/(8 etal)` `:. eta=(pi p r^(2))/(8 Vl) ""...(1)` `=(3.14xx10^(6)xx(0.1)^(4))/(8xx50xx0.25)` `=3.14` POISE Relative error in `eta` `(Delta eta)/(eta)=((Deltar)/(r))+((DeltaV)/(V))+((Deltal)/(L)) "" [ :. (pi)/(8)` CONSTANT ] `=4xx(0.001)/(0.1)+(0.01)/(0.25)+(0.1)/(50)` `=0.04+0.04+0.002` `=0.082` `:.(Delta eta)/(3.14)=0.082` `:.Delta eta=0.0082xx3.14` `=0.25748~~0.257` `:. eta+Deltan=(3.14+-0.257)` Poise OR Second method : `(Delta eta)/(eta)XX100%=0.082xx100%` `=8.2` `:. eta=3.14+-8.2%` Poise