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If an experiment to measure coefficient of viscosity radius of tube measured r = (0.100 +- 0.001) cm and length 1 = (50.0 +- 0.1) cm and volume of fluid coming out of capillary in unit time is V = (0.25 +-0.01) cm//^(2). If pressure difference between end of tube is p = 10^(6) dyne/ cm^(2), then by using Poeisullie's law V=(pi pr^(4))/(8 eta l) Find coefficient of viscosity.

Answer» <html><body><p></p>Solution :By using Poesullie.s law. <br/> `V=(pi p r^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))/(8 etal)` <br/> `:. eta=(pi p r^(2))/(8 Vl) ""...(1)` <br/> `=(3.14xx10^(6)xx(0.1)^(4))/(8xx50xx0.25)` <br/> `=3.14` <a href="https://interviewquestions.tuteehub.com/tag/poise-601896" style="font-weight:bold;" target="_blank" title="Click to know more about POISE">POISE</a> <br/> Relative error in `eta` <br/> `(Delta eta)/(eta)=((Deltar)/(r))+((DeltaV)/(V))+((Deltal)/(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)) "" [ :. (pi)/(8)` <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> ] <br/> `=4xx(0.001)/(0.1)+(0.01)/(0.25)+(0.1)/(50)` <br/> `=0.04+0.04+0.002` <br/> `=0.082` <br/> `:.(Delta eta)/(3.14)=0.082` <br/> `:.Delta eta=0.0082xx3.14` <br/> `=0.25748~~0.257` <br/> `:. eta+Deltan=(3.14+-0.257)` Poise <br/> OR <br/> Second method : <br/> `(Delta eta)/(eta)<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a>%=0.082xx100%` <br/> `=8.2` <br/> `:. eta=3.14+-8.2%` Poise</body></html>


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