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If ax = (x + y + z)y , ay = (x + y + z)z , az = (x + y + z)x , then:(a) 3(x + y + z) = a (b) 2a = x + y + z (c) x + y + z = 0 (d) x = y = z = a/3 |
Answer» (d) \(\frac{a}{3}.\) ax . ay . az = (x + y + z)x + y + z ⇒ ax + y + z = (x + y + z)x + y + z ⇒ a = (x + y + z) Now, (x + y + z)y = ax (given) ⇒ (x + y + z)y = (x + y + z)x ⇒ y = x Similarly, y = z and z = x. ∴ x = y = z = \(\frac{x+y+z}{3}\) = \(\frac{a}{3}.\) |
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