If b = 0, c < 0, is it true the roots of x2 + bx + c = 0 are numerical – InterviewSolution

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1.

If b = 0, c < 0, is it true the roots of x2 + bx + c = 0 are numerically equal and opposite in sign? Justify your answer.

Answer»

Yes, the roots will be equal and opposite in sign.

Given, x² + bx + c = 0, b = 0, c < 0

⇒ x² – c = 0

\(x = \pm \sqrt c\)

Hence, the roots are equal and opposite in sign.

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