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If D and E are points on sides AB and AC respectively of a Δ ABC such that DE II BC and BD = CE. Prove that Δ ABC is isosceles. |
Answer» We have DE∥BC by the converse of proportionality theorem AD/DB=AE/EC AD/DB=AE/DB [BD=CE] AD=AE Adding D both sides AD+BD=AE+DB AD+BD=AE+EC [BD=CE] AB=AC ⊿ABC is isosceles |
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