1.

If D and E are points on sides AB and AC respectively of a Δ ABC such that DE II BC and BD = CE. Prove that Δ ABC is isosceles.

Answer»

We have DE∥BC 

by the converse of proportionality theorem 

AD/DB=AE/EC 

AD/DB=AE/DB [BD=CE] 

AD=AE 

Adding D both sides 

AD+BD=AE+DB 

AD+BD=AE+EC [BD=CE] 

AB=AC 

⊿ABC is isosceles



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