1.

If f(x)=3x^(2)+4x+5, what must the value of k equal so that the graph of f(x-k) will be symmetric to the y-axis?

Answer»

`-4`
`-(4)/(3)`
`-(2)/(3)`
`(2)/(3)`

Solution :Graph `y=3x^(2)+4x+5` in the standard window, and observe that the graph MUST be moved SLIGHTLY to the right to be symmetric to the y-axis. Therefore, k must be positive. Use CALC/minimum to find the vertex of the PARABOLA and observe that its
x-coordinate is -0.66666. . ..if the function entered into `Y_(1)`, set `Y_(2)=Y_(1)(x-(2)/(3))`
and graph `Y_(2)` to verify this answer.


Discussion

No Comment Found

Related InterviewSolutions