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    				| 1. | If foci of an ellipse are (-2,3),(5,9) & 2x+3y+15=0 is tangent to the ellipse. Then find the point of contact the tangent cannot be | 
| Answer» `((7)/(2),-1)` where `S_(2)^(')` is the point of reflection of `S_(2)` inL. `S_(2)^(')=(-11,-15)` So line joining `S_(1)&S_(2)^(')` is given by `(y-3)=2(x+2)` `y-3=2x+4` `2x-y+7=0` So point `P` will be the point of intersection of `2x-y+7=0&2x+3y+15=0` so point P will be the point of intersection of `2x-y+7=0&2x+3y+15=0` i.e., `(-(9)/(2),-2)` | |