1.

If G(g), H(h) and P(p) are centroid' orthocentre and circumcentre of a triangle and x p+y h+z g=0, then (x, y, z) is equal to

Answer»

1, 1, -2
2, 1, -3
1, 3, -4
2, 3, -5

Solution :We know that, orthocentre, entroid and circumentre of a triangle are COLLINEAR and CENTROID DIVIDES orthocentre and cicumcentre in the ratio `2:1`

By USING internally division,
`(2p+1h)/(2+1)=g implies2p+h-3g=0`
But it is given, ` xp+yh+zg=0`
`thereforex=2, y=1 and z=-3`


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