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If `int(1)/(x^(3)+x^(4))dx=(A)/(x^(2))+(B)/(x)+log|(x)/(x+1)|+C` , thenA. `A=(1)/(2), B=1`B. `A=1, B=-(1)/(2)`C. `A=-(1)/(2), B=1`D. A = 1, B = 1 |
Answer» Correct Answer - C `int(dx)/(x^(4)+x^(3))=int((x+1)-x)/(x^(3)(x+1))dx=int((1)/(x^(3))-(1)/(x^(2)(x+1)))dx` `=int((1)/(x^(3))-(1)/(x^(2))+(1)/(x(x+1)))dx` `=int((1)/(x^(3))-(1)/(x^(2))+(1)/(x)-(1)/(x+1))dx` `=-(1)/(2x^(2))+(1)/(x)+log|x|-log|x+1|+C` `-(1)/(2x^(2))+(1)/(x)+log|(x)/(x+1)|+C` `therefore" "A=-(1)/(2) and B=1` |
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