If `l_(1)=int sin^(-1)x dx` and `l_(2) =int sin^(-1)sqrt(1-x^(2))dx`, thenA. `l_(1)=l_(2)`B. `l_(2)=(pi)/(2)l_(1)`C. `l_(1)+l_(2)=(pi)/(2)x`D. `l_(1)+l_(2)=(pi)/(2)`

If `l_(1)=int sin^(-1)x dx` and `l_(2) =int sin^(-1)sqrt(1-x^(2))dx`,

1.	If `l_(1)=int sin^(-1)x dx` and `l_(2) =int sin^(-1)sqrt(1-x^(2))dx`, thenA. `l_(1)=l_(2)`B. `l_(2)=(pi)/(2)l_(1)`C. `l_(1)+l_(2)=(pi)/(2)x`D. `l_(1)+l_(2)=(pi)/(2)`
Answer» Correct Answer - C Given, `l_(1)=int sin^(-1)xdx` and `l_(2)=int sin^(-1)sqrt(1-x^(2))dx rArr l_(2)=int cos^(-1)xdx` Now, `l_(1)+l_(2)=int(sin^(-1)x+cos^(-1)x)dx=int(pi)/(2)dx=(pi)/(2)x` `therefore" "l_(1)+l_(2)=(pi)/(2)x`