InterviewSolution
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InterviewSolution
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If ∧m and ∧0 are the molar conductivities of a weak electrolyte at concentration C and at zero concentration, then the dissociation constant Ka is given by :(a) Ka = \(\frac{∧^2_m\times C}{∧_0-∧_m}\)(b) Ka = \(\frac{∧^2_m\times C}{∧_0(∧_0-∧_m)}\) (c) Ka = \(\frac{∧^2_0\times C}{(∧_0-∧_m)}\) (d) Ka = \(\frac{∧_m\times C}{∧_0(∧_0-∧_m)}\) |
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Answer» Option : (b) Ka = \(\frac{∧^2_m\times C}{∧_0(∧_0-∧_m)}\) |
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