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If m times the mth term of an AP is equal to n times its nth term, then show that (m + n)th term of an AP is zero. |
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Answer» Let a be the first term d be the common difference of the given AP. Then, `T_(m) = a + (m-1)d "and" T_(n) = a + (n-1)d.` Now, `(m * T_(m)) = (n * T_(n)) rArr m * {a+ (m-1)d} = n * {a +(n-1)d}` `rArr a * (m-n) + {(m^(2) -n^(2)) - (m-n)} * d = 0` `rArr (m-n) * {a + (m +n -1)}d.` `rArr (m-n) * T_(m+n) = 0` `rArr T_(m+n) = 0 [because (m-n) ne 0].` Hence, the (m+n)th term is zero. |
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