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If n = 5, how many electrons can have `m_(l) = +1`? |
Answer» When n = 5, l = 0, 1, 2 , 3 and 4 When l = 0, `m != +1` When l = 1, 2, 3, or 4, in each case, there is one orbital which has `m_(l) = +1` `(l = 1, m = -1, 0 +1, l = 2, m = -2, -1, 0 +1, +2`, etc) Hence, there are four orbitals which will have `m_(l) = +1` EAch orbital can have maximum two electrons. Hence, electrons with n = 5 and `m_(l) + 1` will be 8 |
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