InterviewSolution
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InterviewSolution
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If n cells each of emf E and internal resistance rare connected in parallel, then the total emf and internal resistances will beA. `epsi, (r)/(n)`B. `epsi,nr`C. `"n"epsi,(r)/(n)`D. `"n"epsi,nr` |
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Answer» Correct Answer - A In the parallel combination, `(epsi_("eq"))/(r_("eq"))=(epsi_(1))/(r_(1))+(epsi_(2))/(r_(2))+,.....+(epsi_(n))/(r_(n))` `(1)/(r_("eq"))=(1)/(r_(1))+(1)/(r_(2))+...+(1)/(r_n)` `(therefore epsi_(1)=epsi_(2)=epsi_(3)=.....=epsi_(n)=epsi and r_(1)=r_(2)=r_(3)=r...r_(n)=r)` `therefore (epsi_("eq"))/(r_("eq))=(epsi)/(r)+(epsi)/(r)+......+(epsi)/(r)=n(epsi)/(r)..(i)` `(1)/(r_("eq"))=(1)/(r)+(1)/(r)+....+(1)/(r)=(n)/(r)` `r_("eq")=r//n...(ii)` From (i) and (ii) `e_("eq")=n(epsi)/(r)xxr_("eq")=nxx(epsi)/(r)xx(epsi)/(n)=epsi` |
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