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If one of the zeroes of the quadratic polynomial (k–1) x2 + k x + 1 is –3, then the value of k is (A) 4/3 (B) -4/3 (C) 2/3 (D) -2/3 |
Answer» (A) 4/3 Explanation: According to the question, -3 is one of the zeros of quadratic polynomial (k-1)x2+kx+1 Substituting -3 in the given polynomial, (k-1)(-3)2+k(-3)+1=0 (k-1)9+k(-3)+1 = 0 9k-9-3k+1=0 6k-8=0 k=8/6 Therefore, k = 4/3 Hence, option (A) is the correct answer. |
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