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If one root of the equation ax2 + x – 3 = 0 is –1, then what is the other root ?(a) \(\frac14\)(b) \(\frac{1}{2}\)(c) \(\frac34\)(d) 1 |
Answer» (c) \(\frac{3}{4}\) Let the other root of the equation ax2 + x – 3 = 0 be α. As (–1) is a root of the given equation, it satisfies the given equation, i.e., a (–1)2 + (–1) –3 = 0 ⇒ a – 1 – 3 = 0 ⇒ a = 4. ∴ The equation becomes 4x2 + x – 3 = 0. Now, product of roots = α x (–1) = – \(\frac{3}{4}\) ∴ α = 3 . |
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