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If one the roots fo the equation `x^(2) +x f(a) + a=0` is the cube of the othere for all `x in R`, then f(x)=A. `x ^(1//4) + x ^(3//4)`B. ` - (x^(1//4) + x ^(3//4))`C. ` x + x ^(3)`D. none of these |
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Answer» Correct Answer - B Let `alpha ` and `alpha^(3)` be the roots of the equation `x^(2) + x f(a) + a=0`. Then, `alpha + alpha^(3) = - f (a) and alpha^(4) = a` `rArr f (a) = -alpha a alpha^(3) = - (a_^(1//4) - a^(3//4)` `rArr f(a) = - (a^(1//4) + a^(3//4))`, where `a = alpha^(4) gt 0` `rArr f(x) = - (x^(1//4) + x^(3//4)), x gt 0` |
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