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if `overlinex` is the mean of `x_(1),x_(2),x_(3),….,x_(n) " then "sum_(n)^(i=1) (x_(i) -overlinex)=?` |
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Answer» Correct Answer - b `overset(n)underset(i=1) sum (x_(i) -overlinex)= (x_(1) - overlinex) +(x_(2) -overlinex) +….+(x_(n) -overlinex)` `= ( x_(1)+x_(2) +…..+ x_(n))-noverlinex= (noverlinex - noverlinex)=0` |
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