If p, q are the zeroes of the polynomial f(x) = x2 + k(x - 1) - c, th

1.	If p, q are the zeroes of the polynomial f(x) = x2 + k(x - 1) - c, then (p - 1)(q - 1) is equal to ......(A) c - 1 (B) 1- c(C) c (D) 1 + c
Answer» The correct option is: (B) 1- c Explanation: Given equation is x² + k(x- 1) - c = x² + kx - (k + c) Since, p and q are the zeroes, ... p + q = -k and pq = -(k+ c) Now, (p - 1) (q - 1) = Pq - q - p + 1 = pq - (p + q)+ 1 = -(k+ c)-(-k) + 1 = -k - c + k + 1 = 1 - c

If p, q are the zeroes of the polynomial f(x) = x2 + k(x - 1) - c, then (p - 1)(q - 1) is equal to ......(A) c - 1 (B) 1- c(C) c (D) 1 + c

Answer»

The correct option is: (B) 1- c

Explanation:

Given equation is x² + k(x- 1) - c

= x² + kx - (k + c)

Since, p and q are the zeroes,

... p + q = -k and pq = -(k+ c)

Now, (p - 1) (q - 1) = Pq - q - p + 1

= pq - (p + q)+ 1 = -(k+ c)-(-k) + 1

= -k - c + k + 1 = 1 - c