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If `p(x)^(4)-2x^(3)+3x^(2)-ax+b` be a polynomial such that when it is divided by x-1 and x+1, remainders are respectively 5 and 19. Determine the remiander when p(x) is divided by x-2. |
Answer» It is given that, `p(1)=5 " " "and" p(-1)=19` `{:(rArr (1)^(4) -2(1)^(3)+3(1)^(2) -a(1)+b=5,|,"Also," (-1)^(4)-2(-1)^(3)+3(-1)^(2)-a(-1)+b=19),(rArr" " 1-2+3-a+b=5,rArr 1+2+3+a+b=19,),(rArr " " -a+b=3......(1),rArr " " a+b=13....(2),):|` Adding (1) and (2), we get, `2b=16 implies b=8` Putting this value of b in (2), we get a=5 `therefore p(x)=x^(4)-2x^(3)+3x^(2)-5x+8` `therefore p(2)=(2)^(4)-2(2)^(3)+3(2)^(2)-5(2)+8=10` So, remainder =10, when p (x) is divided by (x-2) |
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