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If `R_(H)` represents Rydberg constant, then the energy of the electron in the ground state of hydrogen atom isA. `- (hc)/(R_(H))`B. `- (1)/(R_(H) ch)`C. `-R_(H) ch`D. `- (R_(H)c)/(h)` |
Answer» Correct Answer - C According to Rydberg formula, `bar(v) = R_(H) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`....(i) According to Bohr model, for an electronic transition, `Delta E = - (2pi^(2) me^(4))/(h^(2)) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))` But `Delta E = hv = (hc)/(lamda) = hc bar(v)` `:. hc bar(v) = - (2pi^(2) me^(4))/(h^(2)) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))` or `bar(v) = - (2pi^(2) me^(4))/(ch^(3)) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`...(ii) Comparing eqns. (i) and (ii) `R_(H) = - (2pi^(2) me^(4))/(ch^(3)) :. E_(1) = - (2pi^(2) me^(4))/(h^(2)) = - R_(H) ch` |
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