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If second overtone of closed pipe and third overtone of open pipe are equal, then find ratio of lengths of both the pipes.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) For a closed pipe of length `L _(1),` second <a href="https://interviewquestions.tuteehub.com/tag/overtone-1144273" style="font-weight:bold;" target="_blank" title="Click to know more about OVERTONE">OVERTONE</a> = third harmonic `= (2n -1) f _(1)` <br/> `= 5 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> ( v )/( <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> L _(1))` <br/> `(because ` Here `n = 3 and f _(1) = (v)/( 4 L _(1)))…(1)` <br/> (ii) For an open pipe of length `L _(2),` <br/> third overtone = <a href="https://interviewquestions.tuteehub.com/tag/fourth-998521" style="font-weight:bold;" target="_blank" title="Click to know more about FOURTH">FOURTH</a> harmonic `= nf._(1)` <br/> `= 4 xx (v)/(2 L _(2))` <br/> `(because ` Here ` n =4 and f ._(1) = (v)/(2 L _(2)))` <br/> Now , as per the statement, `(5v)/( 4 L _(1)) = (4v )/( 2 L _(2))`<br/> `therefore (L _(1))/( L _(2)) = (10)/( 16) = 5/8`</body></html>


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