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If Simple interest on a certain sum of money for 3 years at 4% per annum is half the compound interest on Rs. 5000 for 2 years at 4% per annum. Then find the sum placed on simple interest.1). Rs. 16002). Rs. 15003). Rs. 14504). Rs. 1700 |
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Answer» ⇒ $(A\; = \;P{\left. {\left( {1\; + \;\frac{r}{{100}}} \right.} \right)^t})$ where P = principal r = rate of INTEREST t = time ⇒ A = 5000(1 + 4/100)2 On solving we get, ⇒ A = 5408 ⇒ CI = A - P = 5408 - 5000 = Rs. 408 ⇒ SI = CI/2 ⇒ Simple interest = 408/2 = Rs. 204 ⇒ SI = (p × R × T)/100 p = pricipal R = rate of interest T = time On solving we get ⇒ 204 = (p × 4 × 3)/100 ⇒ P = Rs. 1700 ∴ Principal amount is Rs. 1700 |
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