1.

If Simple interest on a certain sum of money for 3 years at 4% per annum is half the compound interest on Rs. 5000 for 2 years at 4% per annum. Then find the sum placed on simple interest.1). Rs. 16002). Rs. 15003). Rs. 14504). Rs. 1700

Answer»

⇒ $(A\; = \;P{\left. {\left( {1\; + \;\frac{r}{{100}}} \right.} \right)^t})$

where

P = principal 

r = rate of INTEREST

t = time

⇒ A = 5000(1 + 4/100)2

On solving we get,

⇒ A = 5408

⇒ CI = A - P = 5408 - 5000 = Rs. 408

SI = CI/2

⇒ Simple interest = 408/2 = Rs. 204

⇒ SI = (p × R × T)/100

p = pricipal

R = rate of interest

T = time

On solving we get

⇒ 204 = (p × 4 × 3)/100 

⇒ P = Rs. 1700

∴ Principal amount is Rs. 1700


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