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If ` sin theta + cos theta = m and sec theta + "cosec" theta = n, ` prove that ` n(m^(2)-1) = 2m. ` |
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Answer» We have ` n(m^(2) -1) = ( sec theta + "cosec" theta )[( sin theta + cos theta)^(2) -1] ` ` = ((1)/(cos theta) + (1)/(sin theta))[(sin^(2)theta + cos^(2)theta) + 2 sin theta cos theta -1 ] ` ` =((sin theta + cos theta))/(sin theta cos theta) * 2 sin theta cos theta ` `=2(sin theta + cos theta)= 2m. ` Hence, `n(m^(2) -1) = 2m. ` |
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