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If sinx+co secx+tany=4 whre x and y in[0,(pi)/(2)] then tan""(y)/(2) is a root of the equation. |
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Answer» `a^(2)+2alpha+1=0` `rArr(TANA)/(1)=(COTB)/(2)=gamma`(SAY) `rArr tan A=gamma` and `tan B=(1)/(2lambda)` `therefore (5-3cos 2A)(5-3cos2B)` `=[5-(3(1-lambda^(2)))/((1+lambda^(2)))]xx[5-(3(1-(1)/(4lambda^(2))))/((1+(1)/(4lambda^(2))))]` |
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