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If \(\sqrt{1369}\) + \(\sqrt{0.0615+X}\) , =37.5, then x is equal to (a) 10–1 (b) 10–2 (c) 10–3 (d) 10 |
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Answer» (c) 10-3 \(\sqrt{1369} +\sqrt{0.0615+X}\) = 37.25 \(\Rightarrow\) \(\sqrt{0.0615+X}\) = 37.25 - \(\sqrt{1369}\) = 37.25 - 37 = 0.25 \(\Rightarrow\) 0.0615 + x = (0.25)2 = 0.0625 \(\Rightarrow\) x = 0.0625 - 0.0615 = 0.001 = \(\frac{1}{10^3}\) = 10-3. |
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