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If ` tan x = (2t)/(1 -t^(2)) " and sin y" = (2t)/(1 + t^(2))` , then the value of ` (dy)/(dx)` isA. 1B. tC. ` ( 1 ) /( 1 - t ) `D. ` ( 1 ) /( 1 + t ) ` |
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Answer» Correct Answer - A Given, ` tan x = ( 2t )/( 1- t ^ 2 ) and sin y = ( 2t ) /( 1 + t ^ 2 ) ` Now,` x =tan ^( -1 ) ( ( 2t ) /( 1- t^ 2)) ` ` x = 2 tan ^( - 1 ) t " " `… (i) and ` y = sin ^( - 1 ) ((2t ) /( 1 + t^2 )) ` ` y = 2 tan ^( -1 ) t " " `... (ii) From Eq. (i) ` (dx )/ ( dt ) = ( 2 )/( 1 +t ^ 2 ) ` From Eq. (ii) ` ( dy )/( dt ) = ( 2 )/( 1 + t^ 2 ) ` ` therefore (dy )/(dx) = ( dy ) /(dt ) xx ( dt ) /( dx ) = ( 2 ) /( (1 + t^ 2 )) xx (( 1 + t^ 2 ))/( 2 ) = 1 ` |
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