1.

If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of `80^@`, then `/_P O A` is equal to

Answer» We can draw the figure as per the given details.
Please refer to the video for the diagram.
We know tangent at any point `P` is always perpendicular to line joining the center `O` of that circle.
So, `/_OAP = /_OBP =90^@`
Now, in `Delta OAP` and `Delta OBP`,
`OA = OB,OP= OP, /_OAP = /_OBP =90^@`
So, `Delta OAP ~ Delta OBP`.
It means, `/_APO = /_BPO`
We are given, `/_APB = 80^@`
So, `/_APO = /_BPO = 80/2 = 40^@`
In `Delta AOP`,
`/_AOP+/_APO+/_OAP = 180^@`
`/_AOP = 180 -40-90 = 50^@`


Discussion

No Comment Found

Related InterviewSolutions