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If the 3rd and the 5th term of an arithmetic progression are 13 and 21, what is the 13th term?1). 532). 493). 574). 61 |
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Answer» Let the first term of AP be a and common difference be d From the problem’s statement ⇒ 3rd term = a + (3 - 1) d = a + 2d = 13----(i) ⇒ 5th term = a + (5 - 1) d = a + 4D = 21----(ii) Now (ii) - (i) ⇒ 2d = 8 ⇒ a = 13 - 8 = 5 Now the 13th term can be given as a + 12d ⇒ 13th term = 5 + 12 × 4 = 53 ∴ the 15th term of AP is 53 |
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