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If the bond dissociation energies of XY, `X_(2)` and `Y_(2)` (all diatomic molecules) are in the ratio of `1 : 1 : 0.5` and `Delta_(f) H` for the formation of XY is `- 200 kJ " mole"^(-1)`. The bond dissociation energy of `X_(2)` will beA. 100 kJ `mol^(-1)`B. 800 kJ `mol^(-1)`C. 300 kJ `mol^(-1)`D. 400 kJ `mol^(-1)` |
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Answer» Correct Answer - B `XYrarrX_((g))+Y_((g)), DeltaH=+"a kJ/mole"^(-1)" .........(i)"` `X_(2)rarr2X, DeltaH=+" a kJ/mole .....(ii)"` `Y_(2)rarr2Y, DeltaH=+0.5" a kJ/mole .......(iii)"` `(1)/(2)xx(ii)+(1)/(2)xx(iii)-(i)`, gives `(1)/(2)X_(2)+(1)/(2)Y_(2)rarrXY,` `DeltaH=(+(a)/(2)+(0.5)/(2)a-a)"kJ/mole"` `+(a)/(2)+(0.5a)/(2)-a=-200` a = 800 |
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