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If the current in primary coil changes at the rate of 120 ampere per second then emf induced in the secondary coil is |
Answer» <html><body><p><strong>Answer:</strong></p><p>Use the <a href="https://interviewquestions.tuteehub.com/tag/formulae-996890" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULAE">FORMULAE</a>, Emf = -(<a class="__cf_email__" data-cfemail="402400" href="/cdn-cgi/l/<klux>EMAIL</klux>-protection">[email protected]</a>)/dt</p><p>where @ == <a href="https://interviewquestions.tuteehub.com/tag/fi-460691" style="font-weight:bold;" target="_blank" title="Click to know more about FI">FI</a></p><p>and, fi = B.i</p><p></p><p>so, emf = -B(di/dt)</p><p>emf = -B(120)</p><p><strong>emf</strong><strong> </strong><strong>=</strong><strong> </strong><strong>-</strong><strong>1</strong><strong>2</strong><strong>0</strong><strong>B</strong></p><p></p><p>if type of coil and <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> is given then calculate B too.</p><p></p><p><strong><em><u>Like and Mark as Brainliest, it <a href="https://interviewquestions.tuteehub.com/tag/really-2240024" style="font-weight:bold;" target="_blank" title="Click to know more about REALLY">REALLY</a> motivates! </u></em></strong></p></body></html> | |