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If the degree of ionization of water is `1.8xx10^(-9)` at `298K`. Its ionization constant will beA. `1.8xx10^(-16)`B. `1xx10^(-14)`C. `1xx10^(-16)`D. `1.67xx10^(-14)` |
Answer» Correct Answer - A `K_(a)=(K_w)/([H_(2)O])=(10^(-14))/(55.5)=1.8xx10^(-16)` . |
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