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If the law of constant compositon is true, what weights of calcium carbon, and oxygen are present in `1.5 g` of calcium carbonate, if a sample of calcium carbonate from another source contains the following percentage composition: `Ca = 40.0%, C = 12.0%`, and `O = 48.0%`? |
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Answer» We have learnt that according to the law of constant proportions, the percentage of the elements presents in different sample of pure of substance always remains the same. This means that in the second sample of calcium carbonate, the ration of the different elements present will remain the same or will remain unchanged. Thus, `"Mass of calcium in 1.5g of the sample"=(40)/(100)xx(1.5g)=0.6g` `"Mass of carbon in 1.5g of the sample"=(12)/(100)xx(1.5g)=0.18g` `"Mass of oxygen in 1.5g of the sample"=(48)/(100)xx(1.5g)=0.72g` |
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