1.

If the letters of the word PREVIOUS be arranged at random, what is the probability that all the vowels come together ?

Answer»

1/14



There are total eight letters 
∴ n(S) = 8PB = 8!
As all vowels should come TOGETHER we assume them as one letter.
 Here E, I, O and U together are taken as one, so the number of letter is 4 + 1 = 5 and it can be arranged in 5P5 = 5! WAYS and the vowels can be arranged in 4! ways among themselves
∴ n(E) = 4! x 5!
∴ P(E) = 4!5! / 8!



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