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If the numbers of different reflexive relations on a set A is equal to the number of different symmetric relations on set A, then the number of elements in A isA. 1B. 3C. 1 and 3D. 3 and 7 |
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Answer» Correct Answer - B Let there be n elements in set A. Then, Number of different reflexive relations on `A=2^(n^(2)-n)` Number of different symmetric relations on `A=2^((n^(2)+n)/(2))` It is given that `2^(n^(2)-n)=2^((n^(2)+n)/(2))` `implies n^(2)-n=(n^(2)+n)/(2)impliesn^(2)-3n=0impliesn(n-3)=0impliesn=3` |
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