InterviewSolution
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InterviewSolution
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If the resistivity of copper is `1.7 xx 10^(-6) Omega cm`, then the mobility of electrons in copper, if each atom of copper contributes one free electron for conduction, is [The amomic weight of copper is `63.54` and its density is `8.96 g//c c]` :A. `23.36 cm^(2)//Vs`B. `503.03cm^(2)//Vs`C. `43.25 cm^(2)//Vs`D. `88.0 cm^(2)//Vs` |
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Answer» Correct Answer - C Mobility of electron `mu =(sigma)/(n e)-(1)` also respectivity `rho = (1)/(sigma)` From Eqs. (i) and (ii), we get `mu = (1)/(n e rho)` Here, `n` = number of free electrons per unit volume `n=(N_(0) xxd)/("atomicweight")` `n=(6.023 xx10^(23) xx8.96)/(63.54) =8.5 xx 10^(22)` From Eqs. (iii) and (iv), we get `mu=(1)/(8.5 xx 10^(22) xx 1.6 xx 10^(-19) xx 1.7 xx 10^(-6))` `:. mu=43.25 cm^(2)//Vs`. |
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