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If the standard hydrogen electrode is used as the reduction electrode, then the emf is given by __________(a) Ered = -E^o + (5/n) log10 [H^+](b) Ered = -E^o – (0.0591/n) log10 [H^+](c) Ered = E^o + (0.0591/n) log10 [H^+](d) Ered = -E^o + (0.0591/n) log10 [H^+]This question was posed to me during an online exam.This intriguing question originated from Types of Fuel Cells in section Electro Chemical Cells and Corrosion of Applied Chemistry

Answer»

The correct choice is (d) ERED = -E^o + (0.0591/n) log10 [H^+]

The EXPLANATION: If the standard hydrogen electrode is USED as the reduction electrode, then the emf can be given by Ered = -E^o + (0.0591/n) log10 [H^+] that is Ered = – EOX.



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