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If the sum and product of the roots of the equation kx2 + 6x + 4k = 0 are equal, then k =A. \(-\frac{3}{2}\)B. \(\frac{3}{2}\)C. \(\frac{2}{3}\)D. \(-\frac{2}{3}\) |
Answer» In the given equation kx2 + 6x + 4k = 0 Sum of the roots = product of the roots (given) – b/a = c/a Here a = k, b = 6 and c = 4k \(-6/k=4k/k\) k = \(-3/2\) |
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